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Download Free Blog Template Web Design

Download 20 responsive Free E-Commerce Template 2017

Wednesday, June 14, 2017 By Maniruzzaman Akash 16 Comments

Download 20 responsive Free E-Commerce Template 2017


Are you looking some best E-Commerce Template? Then see the following free and responsive E-Commerce template and download now.
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Numerical Methods

Numerical method Codes simple MatLab implementation

Monday, June 12, 2017 By Maniruzzaman Akash 0 Comments

Numerical method Codes simple MatLab implementation

In this tutorial, we;ll learn about following MAT LAB works of Numerical Methods.

  1. Numerical Method Simpson 1/3 MatLab Code implementation
  2. Numerical Method Simpson 3/8  MatLab Code implementation
  3. Numerical Method Gauss Elimination MatLab Code Implementation
  4. Numerical Method Gauss Elimination MatLab Code Implementation:
  5. Numerical Method Gauss Zordan MatLab Code Implementation
  6. Numerical Method Gauss Cramers Rule MatLab Code Implementation
  7. Numerical Method Newton Raphson MatLab Code Implementation
  8. Numerical Method Fixed Point Iteration MatLab Code Implementation
  9. Numerical Method False Position Method MatLab Code Implementation
  10. Numerical Method Bisection Method MatLab Code Implementation
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Numerical Methods

Numerical Methods 20 Multiple Choice Questions and Answers

By Maniruzzaman Akash 2 Comments

Numerical Methods Question and Fill in the Blanks



In which of the following method, we approximate the curve of solution by the tangent in each interval.

a.       Picard’s method
b.      Euler’s method
c.       Newton’s method
d.      Runge Kutta method

Ans- B

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Web Design Web Development

How to redirect one page URL to another page URL by javascript

Saturday, May 27, 2017 By Maniruzzaman Akash 1 Comments

Question:

How to redirect one page URL to another page URL by JavaScript?


Solution:

We can use PHP for redirecting one page to another. But it is simple to redirect multiple url redirection from one URL to other URL by JavaScript easily.

See the Simple pseudo code of javascript page redirection,

<script>
if(window.location.href == 'old_url')
{
    window.location.href="new_url";
}


//More url's redirect
if(window.location.href == 'old_url2')
{
    window.location.href="new_url2";
}
</script>

And real life example for that is:

<script>
if(window.location.href == 'https://test.com')
{
    window.location.href="https://another.com";}


//More url's redirect
if(window.location.href == 'https://test.com/new-post')
{
    window.location.href="https://another.com/duplicate-post";}
</script>



Tags: Website redirect by javascript, Website redirects, Redirection of a site, How to redirect one page URL to another page URL by JavaScript, How to redirect one page to another page  by javascript, Blogger page redirect, how to redirect a blogger page to another page, redirect html page, how to redirect html site to another site, how to redirect one site to another site


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C Programming My Videos

URI 1003 online judge solution in C language - video

Friday, May 26, 2017 By Maniruzzaman Akash 0 Comments

URI 1003 online judge solution in C language - video


Main site of URI 1003 Code solution - http://onlinejudgesolution.blogspot.com/2017/05/uri-online-judge-solution-1003-simple.html - URI 1003 code in C,C++,Java,Python and C#

YouTube video link of URI 1003 solution - https://www.youtube.com/watch?v=M9DH_YTCAIk



Tags: URI 1003 solution, URI Simple sum solution video, URI 1003 code in C,C++,Java,Python and C#
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C Programming My Videos

URI 1002 online judge solution in C language - video

By Maniruzzaman Akash 0 Comments

URI 1002 online judge solution in C language - video


Main site of URI 1002 Code - http://onlinejudgesolution.blogspot.com/2017/05/uri-online-judge-solution-1002-area-of.html

Youtube video link of URI 1002 solution - https://www.youtube.com/watch?v=hWG4itUg4CY



Tags: URI 1002 solution, URI Area of a circle solution video
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C Programming My Videos

URI 1001 online judge solution in C language - video

By Maniruzzaman Akash 0 Comments

URI 1001 online judge solution in C language - video


Main site of URI 1001 Code - http://onlinejudgesolution.blogspot.com/2015/10/ura-online-judge-solution-1001-uri.html

Youtube video link of URI 1001 solution - https://www.youtube.com/watch?v=gfF-vT0BHoo



Tags: URI 1001 solution, URI extremely Basic solution video, URI 1001 solution in C
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Blogger Tips

How to remove footer credit from blogger in 3 minutes video with description

Thursday, May 25, 2017 By Maniruzzaman Akash 0 Comments

Simple Tutorial On - How to remove Footer Credit from Blogger.

Simple Steps: 


  1. Open Blogger Themes from the left navigation bar
  2. Find footer pressing    ctrl+f 
  3. Find the link/href of <a> for which this is redirected.
  4. In that <a href="xx.com">XX</a> 
  5. Change it to <a style="visibility: hidden" href="xx.com">XX</a>
  6. Then Finish now footer credit will be removed and you can add your own footer credit in Blogger

See the video for more clear. Only 3 minutes video.








Tags: Blogger Footer credit remove, how to remove blogger footer credit,How to remove footer credit from blogger template, Blogger template, Blogger remove system of footer credit, remove footer credit, Blogger credit remove system
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Blogger Tips

How to redirects blogger homepage to another page 3 minute video

Wednesday, May 24, 2017 By Maniruzzaman Akash 0 Comments

How to redirects blogger homepage to another page 3 minute video

Simple blogger tutorial on redirect blogger homepage to another page.



Tags: Blogger Homepage redirection, How to redirects blogger homepage to another page
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Numerical Methods

False Position method code implementation in Matlab

Tuesday, May 2, 2017 By Maniruzzaman Akash 2 Comments

False Position method code implementation in Matlab

Problem of False position method:
Find the root of the following function where function = 5 * x^4 - 2.7 * x^2 - 2*x + 0.5 
User can take upper limit, lower limit and exact integral.


Code Implementation:



%Function
f = @(x) 5 * x^4 - 2.7 * x^2 - 2*x + 0.5;
l = input('Enter Lower Limit : ');
u = input('Enter Upper Limit : ');
previous_approximation = 0;

f_l = feval(f, l);
f_u = feval(f, u);
root = u -((f_u * (l-u))/ (f_l - f_u));
given_absoulte_error = input('Enter absolute error : ');
absolute_error = abs((root - previous_approximation) / root ) * 100;
previous_approximation = root;

while(absolute_error > given_absoulte_error)
    f_l = feval(f, l);
    f_u = feval(f, u);
    f_root = feval(f, root);
    
    if(f_l * f_root > 0)
        l = root;
    else
        u = root;
    end;
    
    f_l = feval(f, l);
    f_u = feval(f, u);
    
    
    root = u -((f_u * (l-u))/ (f_l - f_u));
    absolute_error = abs((root - previous_approximation) / root ) * 100;
    previous_approximation = root;
    
    fprintf('Root %f Error %f\n', root, absolute_error);
    
end;

disp('-------------------------------');
fprintf('Final Root = %f and absolute error = %f', root, absolute_error);
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