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Artificial Intelligenece C Programming Data Structure

BFS, DFS, DLS in Tree implementation in C

Monday, April 24, 2017 By Maniruzzaman Akash 1 Comments
The solutions of these problems are here:


  1. Breadth First Search program (BFS) using Binary Search tree implementation in C language
  2.  Depth First Search program (DFS) using Binary Search tree implementation in C language
  3. Depth Limited Search(DLS) using Binary Search tree implementation in C language

Algorithms:

Breadth First Search (BFS) algrorithm:

Mark the starting node of the graph as visited and enqueue it into the queue
While the queue is not empty
    Dequeue the next node from the queue to become the current node
       While there is an unvisited child of the current node
       Mark the child as visited and enqueue the child node into the queue

Breadth First Search, Depth First Search and Depth Limited Search Code :

-------------------------------
#include<stdio.h>
#include<stdlib.h>

int queue[100];
int front=0;
int rear=-1;


struct node{
    int data;
    struct node *left;
    struct node *right;
};

/**Insert data in the tree**/
struct node *insert(struct node *root, int value){
    if(root == NULL){
        root = (struct node*) malloc(sizeof(struct node));
        root->left = root->right = NULL;
        root->data = value;
        return root;
    }else{
        if(value < root->data){
            root->left = insert(root->left, value);
        }else{
            if(value > root->data){
                root->right = insert(root->right, value);
            }
        }
        return root;
    }
};

void printNode(struct node *root){
    if(root != NULL) {
        printf("%d ", root->data);
    }
}

/******** Queue ********/
void enqueue(struct node *root){
    if(root != NULL){
        rear++;
        queue[rear] = root;
    }
}
void dequeue(){
    if(rear>=front){
        struct node *root = queue[front];
        printNode(root);
        front++;
        enqueue(root->left);
        enqueue(root->right);
    }
}

/** BFS function **/
void bfs(struct node *root){
    if(root != NULL){
        enqueue(root);
        do{
            dequeue(root);
        }while(front <= rear);
    }
}

/**DFS function **/
void dfs(struct node *root){
    if(root != NULL){
        dfs(root->left);
        dfs(root->right);
        printf("%d ", root->data);
    }
}


/**DLS function**/
void dls(struct node *root, int i, int limit){
    for(i = 0; i < limit; i++){
        if(root != NULL){
            if(limit > 0){
                dls(root->left, i, limit-1 );
                dls(root->right, i, limit-1 );
                printf("%d ", root->data);
            }

        }
        //printf("\n");
    }
}


int main(){

    struct node *root = NULL;
    int choose;
    int n=0, i=0, insertNode, limit;

    printf("Enter Your choice : \n 1 For insert a node \n 2 For BFS \n 3 for DFS\n 4 for DLS\n 0 for exit the program");
    printf("\n---------------------------------");
    while(1){
        printf("\nEnter your option : ");
        scanf("%d", &choose);
        switch(choose){
        case 1:

            printf("How many nodes of the tree :");
            scanf("%d", &n);
            for(i = 0; i < n; i++ ){
                printf("Enter root : ");
                scanf("%d", &insertNode);
                root = insert(root, insertNode);
            }
            break;

        case 2:
            printf("BFS traversal of that tree is : ");
            bfs(root);
            break;

        case 3:
            printf("DFS traversal of that tree is : ");
            dfs(root);
            break;

        case 4:
            printf("Enter the depth limit for DLS: ");
            scanf("%d", &limit);
            dls(root, 0, limit);
            break;

        case 0:
            exit(0);
            break;
        }
    }
}

/** My input

node Number  : 7
20 15 25 10 18 22 28

/** My input **/
-------------------------------

Artificial Intelligenece
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Maniruzzaman Akash, an enthusiastic programmer, a web developer

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1 comment:

  1. AnonymousMarch 13, 2022 at 7:38 AM

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